gremlin-test/features/filter/Sample.feature

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Feature: Step - sample()

  Scenario: g_E_sampleX1X
    Given the modern graph
    And the traversal of
      """
      g.E().sample(1)
      """
    When iterated to list
    Then the result should have a count of 1

  Scenario: g_E_sampleX2X_byXweightX
    Given the modern graph
    And using the parameter v1Id defined as "v[marko].id"
    And the traversal of
      """
      g.E().sample(2).by("weight")
      """
    When iterated to list
    Then the result should have a count of 2

  Scenario: g_V_localXoutE_sampleX1X_byXweightXX
    Given the modern graph
    And the traversal of
      """
      g.V().local(__.outE().sample(1).by("weight"))
      """
    When iterated to list
    Then the result should have a count of 3

  Scenario: g_V_group_byXlabelX_byXbothE_weight_sampleX2X_foldX
    Given the modern graph
    And the traversal of
      """
      g.V().group().by(T.label).by(__.bothE().values("weight").sample(2).fold())
      """
    When iterated to list
    Then nothing should happen because
      """
      The return value of this traversal is a map of samples weights in a list for each key which makes it
      especially hard to assert with the current test language established and the non-deterministic outcomes
      of sample().
      """

  Scenario: g_V_group_byXlabelX_byXbothE_weight_fold_sampleXlocal_5XX
    Given the modern graph
    And the traversal of
      """
      g.V().group().by(T.label).by(__.bothE().values("weight").fold().sample(Scope.local, 5))
      """
    When iterated to list
    Then nothing should happen because
      """
      The return value of this traversal is a map of samples weights in a list for each key which makes it
      especially hard to assert with the current test language established and the non-deterministic outcomes
      of sample().
      """