gremlin-test/features/map/Min.feature

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Feature: Step - min()

  Scenario: g_V_age_min
    Given the modern graph
    And the traversal of
      """
      g.V().values("age").min()
      """
    When iterated to list
    Then the result should be unordered
      | result |
      | d[27].i |

  Scenario: g_V_foo_min
    Given the modern graph
    And the traversal of
      """
      g.V().values("foo").min()
      """
    When iterated to list
    Then the result should be empty

  Scenario: g_V_name_min
    Given the modern graph
    And the traversal of
      """
      g.V().values("name").min()
      """
    When iterated to list
    Then the result should be unordered
      | result |
      | josh |

  Scenario: g_V_age_fold_minXlocalX
    Given the modern graph
    And the traversal of
      """
      g.V().values("age").fold().min(Scope.local)
      """
    When iterated to list
    Then the result should be unordered
      | result |
      | d[27].i |

  Scenario: g_V_foo_fold_minXlocalX
    Given the modern graph
    And the traversal of
      """
      g.V().values("foo").fold().min(Scope.local)
      """
    When iterated to list
    Then the result should be empty

  Scenario: g_V_name_fold_minXlocalX
    Given the modern graph
    And the traversal of
      """
      g.V().values("name").fold().min(Scope.local)
      """
    When iterated to list
    Then the result should be unordered
      | result |
      | josh |

  Scenario: g_V_repeatXbothX_timesX5X_age_min
    Given the modern graph
    And the traversal of
      """
      g.V().repeat(__.both()).times(5).values("age").min()
      """
    When iterated to list
    Then the result should be unordered
      | result |
      | d[27].i |

  Scenario: g_V_hasLabelXsoftwareX_group_byXnameX_byXbothE_weight_minX
    Given the modern graph
    And the traversal of
      """
      g.V().hasLabel("software").group().by("name").by(__.bothE().values("weight").min())
      """
    When iterated to list
    Then the result should be unordered
      | result |
      | m[{"ripple":"d[1.0].d","lop":"d[0.2].d"}] |

  Scenario: g_V_foo_injectX9999999999X_min
    Given the modern graph
    And using the parameter injectVal defined as "d[9999999999].l"
    And the traversal of
      """
      g.V().values("foo").inject(injectVal).min()
      """
    When iterated to list
    Then the result should be unordered
      | result |
      | d[9999999999].l |