| # Licensed to the Apache Software Foundation (ASF) under one |
| # or more contributor license agreements. See the NOTICE file |
| # distributed with this work for additional information |
| # regarding copyright ownership. The ASF licenses this file |
| # to you under the Apache License, Version 2.0 (the |
| # "License"); you may not use this file except in compliance |
| # with the License. You may obtain a copy of the License at |
| # |
| # http://www.apache.org/licenses/LICENSE-2.0 |
| # |
| # Unless required by applicable law or agreed to in writing, |
| # software distributed under the License is distributed on an |
| # "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY |
| # KIND, either express or implied. See the License for the |
| # specific language governing permissions and limitations |
| # under the License. |
| |
| Feature: Step - V() |
| |
| Scenario: g_VX1X_V_valuesXnameX |
| Given the modern graph |
| And using the parameter vid1 defined as "v[marko].id" |
| And the traversal of |
| """ |
| g.V(vid1).V().values("name") |
| """ |
| When iterated to list |
| Then the result should be unordered |
| | result | |
| | marko | |
| | vadas | |
| | lop | |
| | josh | |
| | ripple | |
| | peter | |
| |
| Scenario: g_V_outXknowsX_V_name |
| Given the modern graph |
| And the traversal of |
| """ |
| g.V().out("knows").V().values("name") |
| """ |
| When iterated to list |
| Then the result should be unordered |
| | result | |
| | marko | |
| | marko | |
| | vadas | |
| | vadas | |
| | lop | |
| | lop | |
| | josh | |
| | josh | |
| | ripple | |
| | ripple | |
| | peter | |
| | peter | |
| |
| Scenario: g_V_hasXname_GarciaX_inXsungByX_asXsongX_V_hasXname_Willie_DixonX_inXwrittenByX_whereXeqXsongXX_name |
| Given the grateful graph |
| And the traversal of |
| """ |
| g.V().has("artist", "name", "Garcia").in("sungBy").as("song"). |
| V().has("artist", "name", "Willie_Dixon").in("writtenBy").where(P.eq("song")).values("name") |
| """ |
| When iterated to list |
| Then the result should be unordered |
| | result | |
| | MY BABE | |
| | HOOCHIE COOCHIE MAN | |
| |
| Scenario: g_V_hasLabelXpersonX_asXpX_VXsoftwareX_addInEXuses_pX |
| Given the empty graph |
| And the graph initializer of |
| """ |
| g.addV("person").property(T.id, 1).property("name", "marko").property("age", 29).as("marko"). |
| addV("person").property(T.id, 2).property("name", "vadas").property("age", 27).as("vadas"). |
| addV("software").property(T.id, 3).property("name", "lop").property("lang", "java").as("lop"). |
| addV("person").property(T.id, 4).property("name","josh").property("age", 32).as("josh"). |
| addV("software").property(T.id, 5).property("name", "ripple").property("lang", "java").as("ripple"). |
| addV("person").property(T.id, 6).property("name", "peter").property("age", 35).as('peter'). |
| addE("knows").from("marko").to("vadas").property(T.id, 7).property("weight", 0.5). |
| addE("knows").from("marko").to("josh").property(T.id, 8).property("weight", 1.0). |
| addE("created").from("marko").to("lop").property(T.id, 9).property("weight", 0.4). |
| addE("created").from("josh").to("ripple").property(T.id, 10).property("weight", 1.0). |
| addE("created").from("josh").to("lop").property(T.id, 11).property("weight", 0.4). |
| addE("created").from("peter").to("lop").property(T.id, 12).property("weight", 0.2) |
| """ |
| And using the parameter xx1 defined as "l[v[lop],v[ripple]]" |
| And using the parameter vid1 defined as "v[marko].id" |
| And using the parameter vid2 defined as "v[vadas].id" |
| And using the parameter vid3 defined as "v[lop].id" |
| And using the parameter vid4 defined as "v[josh].id" |
| And using the parameter vid5 defined as "v[ripple].id" |
| And using the parameter vid6 defined as "v[peter].id" |
| And the traversal of |
| """ |
| g.V().hasLabel("person").as("p").V(xx1).addE("uses").from("p") |
| """ |
| When iterated to list |
| Then the result should have a count of 8 |
| And the graph should return 8 for count of "g.E().hasLabel(\"uses\")" |
| And the graph should return 2 for count of "g.V(vid1).outE(\"uses\")" |
| And the graph should return 2 for count of "g.V(vid2).outE(\"uses\")" |
| And the graph should return 4 for count of "g.V(vid3).inE(\"uses\")" |
| And the graph should return 2 for count of "g.V(vid4).outE(\"uses\")" |
| And the graph should return 4 for count of "g.V(vid5).inE(\"uses\")" |
| And the graph should return 2 for count of "g.V(vid6).outE(\"uses\")" |