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// Copyright 2006, 2007 The Apache Software Foundation
//
// Licensed under the Apache License, Version 2.0 (the "License");
// you may not use this file except in compliance with the License.
// You may obtain a copy of the License at
//
// http://www.apache.org/licenses/LICENSE-2.0
//
// Unless required by applicable law or agreed to in writing, software
// distributed under the License is distributed on an "AS IS" BASIS,
// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
// See the License for the specific language governing permissions and
// limitations under the License.
package org.apache.tapestry5.ioc.internal.util;
/**
* Logic for handling one shot semantics for classes; classes that include a method (or methods) that "locks down" the
* instance, to prevent it from being used again in the future.
*/
public class OneShotLock
{
private boolean lock;
/**
* Checks to see if the lock has been set (via {@link #lock()}).
*
* @throws IllegalStateException if the lock is set
*/
public synchronized void check()
{
innerCheck();
}
private void innerCheck()
{
if (lock)
{
// This is how I would think it would be:
// [0] is getStackTrace()
// [1] is innerCheck()
// [2] is check() or lock()
// [3] is caller of check() or lock()
// ... so why do we get element 4? Found this via trial and error. Some extra stack frame
// gets in there somehow, as in, getStackTrace() must be calling something (probably native)
// that creates the actual array, and includes itself as [0], getStackTrace() as [1], etc.
// Maybe it's something to do with synchronized?
StackTraceElement element = Thread.currentThread().getStackTrace()[4];
throw new IllegalStateException(UtilMessages.oneShotLock(element));
}
}
/**
* Checks the lock, then sets it.
*/
public synchronized void lock()
{
innerCheck();
lock = true;
}
}