Allow Namespace to be Set When Setting an API Host
- Fix bug that prevents a namespace from being set at the same time the API is set
- Add test to ensure this case always works
diff --git a/tests/src/whisk/core/cli/test/WskBasicUsageTests.scala b/tests/src/whisk/core/cli/test/WskBasicUsageTests.scala
index 6be5cab..eb34c31 100644
--- a/tests/src/whisk/core/cli/test/WskBasicUsageTests.scala
+++ b/tests/src/whisk/core/cli/test/WskBasicUsageTests.scala
@@ -97,6 +97,21 @@
stdout should include regex ("""(?i)whisk API version\s+v1""")
}
+ it should "set apihost, auth, and namespace" in {
+ val tmpwskprops = File.createTempFile("wskprops", ".tmp")
+ try {
+ val namespace = wsk.namespace.list().stdout.trim.split("\n").last
+ val env = Map("WSK_CONFIG_FILE" -> tmpwskprops.getAbsolutePath())
+ val stdout = wsk.cli(Seq("property", "set", "-i", "--apihost", wskprops.apihost, "--auth", wskprops.authKey,
+ "--namespace", namespace), env = env).stdout
+ stdout should include (s"ok: whisk auth set to ${wskprops.authKey}")
+ stdout should include (s"ok: whisk API host set to ${wskprops.apihost}")
+ stdout should include (s"ok: whisk namespace set to ${namespace}")
+ } finally {
+ tmpwskprops.delete()
+ }
+ }
+
it should "show api build version using property file" in {
val tmpwskprops = File.createTempFile("wskprops", ".tmp")
try {
