Use Default Namespace if the Property is Blank
- Use _ as the namespace if the NAMESPACE property in .wskprops is set to blank
diff --git a/tests/src/whisk/core/cli/test/WskBasicUsageTests.scala b/tests/src/whisk/core/cli/test/WskBasicUsageTests.scala
index db709e7..da194e7 100644
--- a/tests/src/whisk/core/cli/test/WskBasicUsageTests.scala
+++ b/tests/src/whisk/core/cli/test/WskBasicUsageTests.scala
@@ -107,6 +107,20 @@
}
}
+ it should "ensure default namespace is used when a blank namespace is set" in {
+ val tmpwskprops = File.createTempFile("wskprops", ".tmp")
+ try {
+ val writer = new BufferedWriter(new FileWriter(tmpwskprops))
+ writer.write(s"NAMESPACE=")
+ writer.close()
+ val env = Map("WSK_CONFIG_FILE" -> tmpwskprops.getAbsolutePath())
+ val stdout = wsk.cli(Seq("property", "get", "-i", "--namespace"), env = env).stdout
+ stdout should include regex ("whisk namespace\\s+_")
+ } finally {
+ tmpwskprops.delete()
+ }
+ }
+
it should "show api build version using property file" in {
val tmpwskprops = File.createTempFile("wskprops", ".tmp")
try {
