| /* |
| FUNCTION |
| <<strpbrk>>---find characters in string |
| |
| INDEX |
| strpbrk |
| |
| ANSI_SYNOPSIS |
| #include <string.h> |
| char *strpbrk(const char *<[s1]>, const char *<[s2]>); |
| |
| TRAD_SYNOPSIS |
| #include <string.h> |
| char *strpbrk(<[s1]>, <[s2]>) |
| char *<[s1]>; |
| char *<[s2]>; |
| |
| DESCRIPTION |
| This function locates the first occurence in the string |
| pointed to by <[s1]> of any character in string pointed to by |
| <[s2]> (excluding the terminating null character). |
| |
| RETURNS |
| <<strpbrk>> returns a pointer to the character found in <[s1]>, or a |
| null pointer if no character from <[s2]> occurs in <[s1]>. |
| |
| PORTABILITY |
| <<strpbrk>> requires no supporting OS subroutines. |
| */ |
| |
| #include <string.h> |
| |
| char *strpbrk(const char *s1, const char *s2) |
| { |
| const char *c = s2; |
| if (!*s1) |
| return (char *) NULL; |
| |
| while (*s1) |
| { |
| for (c = s2; *c; c++) |
| { |
| if (*s1 == *c) |
| break; |
| } |
| if (*c) |
| break; |
| s1++; |
| } |
| |
| if (*c == '\0') |
| s1 = NULL; |
| |
| return (char *) s1; |
| } |
