update component name generate method
In case weex page is composed by separate weex component jsbundles whose entry filename are `index.we`, which makes every bundle compiles as:
```
__weex_define__('@weex-component/f5e1c456d74a6374b2c0129d79c108e1', [], function(__weex_require__, __weex_exports__, __weex_module__) {
__weex_script__(__weex_module__, __weex_exports__, __weex_require__)
if (__weex_exports__.__esModule && __weex_exports__.default) {
__weex_module__.exports = __weex_exports__.default
}
__weex_module__.exports.template = __weex_template__
__weex_module__.exports.style = __weex_style__
})
__weex_bootstrap__('@weex-component/f5e1c456d74a6374b2c0129d79c108e1',undefined,undefined)
```
As shown above, `md5('index.we') === "f5e1c456d74a6374b2c0129d79c108e1"`.
So this commit suggests to generate component name based on file content instead of file name to avoid this problem.diff --git a/src/loader.js b/src/loader.js
index b0825b4..6859389 100644
--- a/src/loader.js
+++ b/src/loader.js
@@ -220,7 +220,7 @@
const isElement = loaderQuery.element
const isEntry = resourceQuery.entry
const filename = path.relative('.', resourcePath)
- const name = isEntry ? md5(filename) :
+ const name = isEntry ? md5(fs.readFileSync(filename)) :
(resourceQuery.name ||
getNameByPath(resourcePath))
