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select time_by_day.the_year as c0, customer.education as c1, customer.yearly_income as c2, sum(sales_fact_1997.store_cost) as m0 from time_by_day as time_by_day, sales_fact_1997 as sales_fact_1997, customer as customer where sales_fact_1997.time_id = time_by_day.time_id and time_by_day.the_year = 1997 and sales_fact_1997.customer_id = customer.customer_id group by time_by_day.the_year, customer.education, customer.yearly_income;