| # Licensed to the Apache Software Foundation (ASF) under one |
| # or more contributor license agreements. See the NOTICE file |
| # distributed with this work for additional information |
| # regarding copyright ownership. The ASF licenses this file |
| # to you under the Apache License, Version 2.0 (the |
| # "License"); you may not use this file except in compliance |
| # with the License. You may obtain a copy of the License at |
| # |
| # http://www.apache.org/licenses/LICENSE-2.0 |
| # |
| # Unless required by applicable law or agreed to in writing, |
| # software distributed under the License is distributed on an |
| # "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY |
| # KIND, either express or implied. See the License for the |
| # specific language governing permissions and limitations |
| # under the License. |
| |
| """ |
| TPC-H Problem Statement Query 22: |
| |
| This query counts how many customers within a specific range of country codes have not placed |
| orders for 7 years but who have a greater than average “positive” account balance. It also reflects |
| the magnitude of that balance. Country code is defined as the first two characters of c_phone. |
| |
| The above problem statement text is copyrighted by the Transaction Processing Performance Council |
| as part of their TPC Benchmark H Specification revision 2.18.0. |
| """ |
| |
| from datafusion import SessionContext, WindowFrame, col, lit |
| from datafusion import functions as F |
| from util import get_data_path |
| |
| NATION_CODES = [13, 31, 23, 29, 30, 18, 17] |
| |
| # Load the dataframes we need |
| |
| ctx = SessionContext() |
| |
| df_customer = ctx.read_parquet(get_data_path("customer.parquet")).select( |
| "c_phone", "c_acctbal", "c_custkey" |
| ) |
| df_orders = ctx.read_parquet(get_data_path("orders.parquet")).select("o_custkey") |
| |
| # The nation code is a two digit number, but we need to convert it to a string literal |
| nation_codes = F.make_array(*[lit(str(n)) for n in NATION_CODES]) |
| |
| # Use the substring operation to extract the first two characters of the phone number |
| df = df_customer.with_column("cntrycode", F.substring(col("c_phone"), lit(0), lit(3))) |
| |
| # Limit our search to customers with some balance and in the country code above |
| df = df.filter(col("c_acctbal") > lit(0.0)) |
| df = df.filter(~F.array_position(nation_codes, col("cntrycode")).is_null()) |
| |
| # Compute the average balance. By default, the window frame is from unbounded preceding to the |
| # current row. We want our frame to cover the entire data frame. |
| window_frame = WindowFrame("rows", None, None) |
| df = df.with_column( |
| "avg_balance", F.window("avg", [col("c_acctbal")], window_frame=window_frame) |
| ) |
| |
| df.show() |
| # Limit results to customers with above average balance |
| df = df.filter(col("c_acctbal") > col("avg_balance")) |
| |
| # Limit results to customers with no orders |
| df = df.join(df_orders, left_on="c_custkey", right_on="o_custkey", how="anti") |
| |
| # Count up the customers and the balances |
| df = df.aggregate( |
| [col("cntrycode")], |
| [ |
| F.count(col("c_custkey")).alias("numcust"), |
| F.sum(col("c_acctbal")).alias("totacctbal"), |
| ], |
| ) |
| |
| df = df.sort(col("cntrycode").sort()) |
| |
| df.show() |