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Feature: Step - peerPressure()
                
  Scenario: g_V_peerPressure_hasXclusterX
    Given the modern graph
    And the traversal of
      """
      g.withComputer().V().peerPressure().has("gremlin.peerPressureVertexProgram.cluster")
      """
    When iterated to list
    Then the result should be unordered
      | result |
      | v[marko] |
      | v[vadas] |
      | v[lop] |
      | v[josh] |
      | v[ripple] |
      | v[peter] |
    And the graph should return 6 for count of "g.withComputer().V().peerPressure().has(\"gremlin.peerPressureVertexProgram.cluster\")"

  Scenario: g_V_peerPressure_byXclusterX_byXoutEXknowsXX_pageRankX1X_byXrankX_byXoutEXknowsXX_timesX2X_group_byXclusterX_byXrank_sumX_limitX100X
    Given the modern graph
    And the traversal of
      """
      g.withComputer().V().peerPressure().by("cluster").by(__.outE("knows")).pageRank(1.0).by("rank").by(__.outE("knows")).times(1).group().by("cluster").by(__.values("rank").sum()).limit(100)
      """
    When iterated to list
    Then the result should be unordered
      | result |
      | m[{"d[1].i":"d[0.5833333333333333].d","d[3].i":"d[0.1388888888888889].d","d[5].i":"d[0.1388888888888889].d","d[6].i":"d[0.1388888888888889].d"}] |

  Scenario: g_V_hasXname_rippleX_inXcreatedX_peerPressure_byXoutEX_byXclusterX_repeatXunionXidentity__bothX_timesX2X_dedup_valueMapXname_clusterX
    Given the modern graph
    And the traversal of
      """
      g.withComputer().V().has("name", "ripple").in("created").peerPressure().by(__.outE()).by("cluster").repeat(__.union(__.identity(), __.both())).times(2).dedup().valueMap("name", "cluster")
      """
    When iterated to list
    Then the result should be unordered
      | result |
      | m[{"name": ["marko"], "cluster": [1]}] |
      | m[{"name": ["vadas"], "cluster": [2]}] |
      | m[{"name": ["lop"], "cluster": [4]}] |
      | m[{"name": ["josh"], "cluster": [4]}] |
      | m[{"name": ["ripple"], "cluster": [4]}] |
      | m[{"name": ["peter"], "cluster": [6]}] |