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"),s("code",[a._v("timestampGenerator")]),a._v("；然后为每一个时间序列创建一个 "),s("code",[a._v("SeriesReaderByTimestamp")]),a._v("，放到 "),s("code",[a._v("allDataReaderList")]),a._v("列表中")]),a._v(" "),s("p",[a._v("初始化完成后，调用 "),s("code",[a._v("nextWithoutConstraint()")]),a._v(" 方法更新结果。如果有为下一个 group by 分区缓存 timestamp，且时间符合要求，则将其加入 "),s("code",[a._v("timestampArray")]),a._v(" 中，否则直接返回 "),s("code",[a._v("aggregateResultList")]),a._v(" 结果；在没有为下一个 group by 分区缓存 timestamp 的情况下，使用 "),s("code",[a._v("timestampGenerator")]),a._v(" 进行遍历：")]),a._v(" "),s("div",{staticClass:"language- line-numbers-mode"},[s("pre",{pre:!0,attrs:{class:"language-text"}},[s("code",[a._v("while (timestampGenerator.hasNext()) {\n // 调用 constructTimeArrayForOneCal() 方法，得到 timestamp 列表\n timeArrayLength = constructTimeArrayForOneCal(timestampArray, timeArrayLength);\n\n // 调用 updateResultUsingTimestamps() 方法，使用 timestamp 列表计算聚合结果\n for (int i = 0; i < paths.size(); i++) {\n aggregateResultList.get(i).updateResultUsingTimestamps(\n timestampArray, timeArrayLength, allDataReaderList.get(i));\n }\n\n timeArrayLength = 0;\n // 判断是否到结束\n if (timestamp >= curEndTime) {\n hasCachedTimestamp = true;\n break;\n }\n}\n")])]),a._v(" "),s("div",{staticClass:"line-numbers-wrapper"},[s("span",{staticClass:"line-number"},[a._v("1")]),s("br"),s("span",{staticClass:"line-number"},[a._v("2")]),s("br"),s("span",{staticClass:"line-number"},[a._v("3")]),s("br"),s("span",{staticClass:"line-number"},[a._v("4")]),s("br"),s("span",{staticClass:"line-number"},[a._v("5")]),s("br"),s("span",{staticClass:"line-number"},[a._v("6")]),s("br"),s("span",{staticClass:"line-number"},[a._v("7")]),s("br"),s("span",{staticClass:"line-number"},[a._v("8")]),s("br"),s("span",{staticClass:"line-number"},[a._v("9")]),s("br"),s("span",{staticClass:"line-number"},[a._v("10")]),s("br"),s("span",{staticClass:"line-number"},[a._v("11")]),s("br"),s("span",{staticClass:"line-number"},[a._v("12")]),s("br"),s("span",{staticClass:"line-number"},[a._v("13")]),s("br"),s("span",{staticClass:"line-number"},[a._v("14")]),s("br"),s("span",{staticClass:"line-number"},[a._v("15")]),s("br"),s("span",{staticClass:"line-number"},[a._v("16")]),s("br"),s("span",{staticClass:"line-number"},[a._v("17")]),s("br")])]),s("p",[a._v("其中的 "),s("code",[a._v("constructTimeArrayForOneCal()")]),a._v(" 方法遍历 timestampGenerator 构建 timestamp 列表：")]),a._v(" "),s("div",{staticClass:"language- line-numbers-mode"},[s("pre",{pre:!0,attrs:{class:"language-text"}},[s("code",[a._v("for (int cnt = 1; cnt < timeStampFetchSize && timestampGenerator.hasNext(); cnt++) {\n timestamp = timestampGenerator.next();\n if (timestamp < curEndTime) {\n timestampArray[timeArrayLength++] = timestamp;\n } else {\n hasCachedTimestamp = true;\n break;\n }\n}\n")])]),a._v(" "),s("div",{staticClass:"line-numbers-wrapper"},[s("span",{staticClass:"line-number"},[a._v("1")]),s("br"),s("span",{staticClass:"line-number"},[a._v("2")]),s("br"),s("span",{staticClass:"line-number"},[a._v("3")]),s("br"),s("span",{staticClass:"line-number"},[a._v("4")]),s("br"),s("span",{staticClass:"line-number"},[a._v("5")]),s("br"),s("span",{staticClass:"line-number"},[a._v("6")]),s("br"),s("span",{staticClass:"line-number"},[a._v("7")]),s("br"),s("span",{staticClass:"line-number"},[a._v("8")]),s("br"),s("span",{staticClass:"line-number"},[a._v("9")]),s("br")])]),s("h2",{attrs:{id:"使用level来汇总降采样的总点数"}},[s("a",{staticClass:"header-anchor",attrs:{href:"#使用level来汇总降采样的总点数"}},[a._v("#")]),a._v(" 使用Level来汇总降采样的总点数")]),a._v(" "),s("p",[a._v("降采样后，我们也可以使用level关键字来进一步汇总点数。")]),a._v(" "),s("p",[a._v("这个逻辑在 "),s("code",[a._v("GroupByTimeDataSet")]),a._v("类里。")]),a._v(" "),s("ol",[s("li",[s("p",[a._v("首先，把所有涉及到的时序按level来进行汇集，最后的路径。")]),a._v(" "),s("blockquote",[s("p",[a._v("例如把root.sg1.d1.s0,root.sg1.d2.s1按level=1汇集成root.sg1。")])])]),a._v(" "),s("li",[s("p",[a._v("然后调用上述的降采样逻辑求出所有时序的总点数信息，这个会返回RowRecord数据结构。")])]),a._v(" "),s("li",[s("p",[a._v("最后，把降采样返回的RowRecord按上述的final paths，进行累加，组合成新的RowRecord。")]),a._v(" "),s("blockquote",[s("p",[a._v("例如，把《root.sg1.d1.s0,3》，《root.sg1.d2.s1，4》聚合成《root.sg1，7》")])])])]),a._v(" "),s("blockquote",[s("p",[a._v("注意:")]),a._v(" "),s("ol",[s("li",[a._v("这里只支持count操作")]),a._v(" "),s("li",[a._v("root的层级level=0")])])])])}),[],!1,null,null,null);e.default=n.exports}}]); |