framework/resources/Functional/aggregates/aggregation/count_distinct/with_sum_avg_c_bigint_group_by_5_cols.sql

select count(distinct c_bigint), sum(c_bigint), round(avg(c_bigint)) from alltypes_with_nulls group by  c_varchar,c_integer,c_bigint,d9,d18 order by  c_varchar,c_integer,c_bigint,d9,d18;